Question

A man is 28 years older than his son After 10 years he will be thrice as old as his son . find their present ages (linear equations )

Answer 1

Let the man's age be 'x' and

his son's age be 'y'.

Given the man is 28 years older than his son,

x=28+y→1

FUTURE:

After 10 years, he'll be thrice the old as his son.

∴x+10=3(y+10)

x+10=3y+30

x-3y=30-10

x-3y=20

Substituing this in 1, we get:

28+y-3y=20

-2y=20-28

-2y=-8

y=-8÷-2

⇒y=4.

Substituting this in 1, we get:

x=28+y

=28+4

∴x=32.

∴The present age of the man is 32 years and his son's is 4 years.

Hope this helps.. c:

Answer 2

Answer: this is the answer

Step-by-step explanation:

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