Question

A man is 28 years older than his son after 10 years his age will be twice the age of his son find their present ages

Answer 1

$\bold{\underline{Question:}}$

A man is 28 years older than his son after 10 years his age will be twice the age of his son. Find their present ages.

$\bold{\underline{Solution:}}$

$\bold{\textsf{Let the son's age be x years.}}\\\\\\\bold{\textsf{So father's age = (x+28) years.}}$

After 10 years ,

• The son's age = ( x+10) years.
• The father's age = (x+28+10) = (x+38) years.

According to question ,

$\implies{\bold{(x+10)2=x+38}}\\\\\\\implies{\bold{2x+20=x+38}}\\\\\\\implies{\bold{2x-x=38-20}}\\\\\\\implies{\bold{x=18}}\\\\\\\bold{\boxed{\textsf{Son's age = x = 18 years.}}}\\\\\\\bold{\boxed{\textsf{Father's age = x+28 = 18 +28 = 46 years.}}}$