Question

A man is 28 years older than his son. After 10 years, the man's age will be three times his son's present age. Find their present ages.​

Answer 1

Step-by-step explanation:

Let the son's age be x years

man is 28 years older than son,

so,

man's age = x + 28 years

After 10 years

man's age = x + 28 + 10 = x + 38 years

son's age = x + 10 years

After 10 years , the man will be thrice as old as his son,

the following balanced equation will be formed

3(x + 10) = x + 38

3x + 30 = x + 38

3x - x = 38 - 30

2x = 8

x = \frac{8}{2}x=

2

8

x = 4

So,

son's age = x = 4 years

man's age = x + 28 = 4 + 28 = 32 years

Answer 2

Answer:

Son present age = 4

Man present age = 32

Step-by-step explanation:

Son present age = x

Man present age = 28 + x

Son age after 10 years = x + 10

Man age after 10 years = 28 + x + 10

OR

Man age after 10 years = 3(x + 10)

Equation = 3(x + 10) = 28 + x + 10

= 3x + 30 = 38 + x

= 3x - x = 38 - 30

= 2x = 8

= x = 8/2

= x = 4

Hence,

Son present age = x = 4

Man present age = 28 + x = 28 + 4 = 32