Question

A man is 28 years older then his son. After 10 years, he will be thrice as old as his son. Find their present age

Answer 1

The answer is as follows....

Answer 2

Answer:

The man is 32 years old and his son is 4 years old.

Step-by-step explanation:

Given :

A man is = 28 years older than his son

After 10 years = he will be thrice as old as his son.

To find :

Their Present age

Solution :

Let the -

• Son as x
• Man be as (x + 28)

$\rule{300}{1.5}$

After 10 years -

• Son = (x + 10)
• Man = (x + 28) + 10

$\rule{300}{1.5}$

According to the Question -

Man will be thrice of his son after 10 years

➙ (x + 28) + 10 = 3(x + 10)

➙ x + 38 = 3x + 30

➙ 3x - x = 38 - 30

➙ 2x = 8

➙ x = 4

Son = 4 years old

$\rule{300}{1.5}$

Father's age =

➙ (4 + 28)

➙ (4 + 28)

➙ 32

Father = 32 years

$\therefore$ The man is 32 years old and his son is 4 years old.