Question

A man is 29 years younger than his father.If the sum of their present ages is 51 years, find the ages of the man and his father​

Answer 1

Given :-

▪ A man is 29 years younger than his father.

▪ Sum of thier present ages is 51 years.

To Find :-

▪ Present ages of the man and his father.

Solution :-

Let us assume the present ages of the man and his father be x and y years.

We are given two cases, which will give us a pair of linear equation in two variables. After then, we can solve for x and y.

Case 1 :-

The man is 29 years younger than his father.

⇒ x + 29 = y

⇒ x - y = -29 ...(1)

Case 2 :-

The sum of thier present ages is 51 years.

⇒ x + y = 51 ...(2)

Adding (1) and (2), we get

⇒ x - y + x + y = -29 + 51

⇒ 2x = 22

⇒ x = 11

Substituting [x = 11] in (2), we have

⇒ 11 + y = 51

⇒ y = 51 - 11

⇒ y = 40

Hence, The age of the man is 11 years and the age of his father is 40 years.

Answer 2

Answer:

QUETION:-

QUETION:-A man is 29 years younger than his father.If the sum of their present ages is 51 years, find the ages of the man and his father.

TO FIND:-

The ages of the man and his father.

GIVEN:-

➜ A man is 29 years younger than his father.

➜ The sum of their present ages is 51 years.

SOLUTION:-

➜ Let us take the present ages of man and his father is x and y years.

➜ We are given two cases,

➜ which will give us a pair of linear equation in two variables.

➜ After then, we can solve for x and y.

EQUATION 1 ➜

A man is 29 years younger than his father.

SO;

=>x+29 = y

=>x-y= - 29__(1)

EQUATION 2 ➜

The sum of thier present age is 51 years

=>x+y = 51__(2)

ADDING (1) AND (2) EQUATIONS:-

=>x-y+x+y= -29 + 51

=>2x = 22

=>x=22/2

=>x=11

PUTTING VALUE (x = 11) IN EQUATION (2)

=>11+y = 51

=>y = 51 - 11

=> y = 40

So NOW:-

The age of the man is => 11 years

The age of man's father is => 40 years

Thanks :)