a man is 3 times as old as his son. after 15 years, he will be only twice as old as his son. find their present ages.
Answers
Answered by
0
Answer:
The son is 15 years old
the man = 45 years years old
Step-by-step explanation:
The age of son = x.
The man will start 3 times older than his son = 3x.
After 15 years:
son's age = x + 15.
man's age = 3x + 15.
Now that the Man is only twice as old as his son.
3x + 15 = 2(x + 15)
3x + 15 = 2x + 30
3x = 2x + 15
x = 15.
This concludes the age of the son is = 15 years.
Leaving the age of the man = 45 years.
Answered by
0
Answer:
let the age of son be x
man age 3x
after 15 years
2x = x+ 15
2x-x =15
x= 15
man age = 3x
= 3× 15
= 45
I hope this will help you
Similar questions