a man is 3 times as old as his son who is 9 years 4 months old. how old will the father be next year
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Answer:
F= Father’s age
S = Son's age
For (Eq1) Father is three times as old as his son:
F = 3S
For (Eq2) In 10 year time the Father age will be twice as old as his son:
F + 10 = 2(S + 10)
F=2S+20–10
F=2S+10 (Eq2)
Then, lets us substitute the (Eq1) into the (Eq2)
3S=2S+10
3S-2S=10
S=10
Then son is 10 years old.
and Father
F=3S so 3 x 10
Father age is 30 years old.
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