Math, asked by vishal0122, 9 months ago

A MAN IS 3 TIMES AS OLD AS IS SON AFTER15 YEARS HE WILL BE TWICE AS OLD AS HIS SON FIND THEIR PRESENT AGES​

Answers

Answered by adarshsingh8882
0

Let the age of son = x.

Then the age of man will be 3 times as old as his son = 3x.

After 15 years:

Age of son = x + 15.

Age of man = 3x + 15.

Given that Man will be only twice as old as his son.

3x + 15 = 2(x + 15)

3x + 15 = 2x + 30

3x = 2x + 15

x = 15.

Therefore the age of son = 15 years.

the age of man = 45 years.

Hope this helps!

Answered by nhorsanglama
0

Answer:

Hope it will help you

Step-by-step explanation:

let son present age be x

father age =3x

After 15 years

   2(x+15)=3x+15

or,2x+30=3x+15

or,x=15

Therefore,

Present age of son=x=15 years

Present age of father=3x=3×15=45 years

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