Math, asked by theragingdune, 9 days ago

A man is 3 years older than 4 times his son's age. 5 years ago, he was 10 times as old as his son. Find the present age of son.
(a) 32 years (b) 4 years (c) 42 years (d) 8 years​

Answers

Answered by alizaahmed122350
4

Let the son's age be x.

Father's age =3x

∴3x−5=4(x−5)

or 3x−5=4x−20

or 20−5=4x−3x or x=15

After 5 years, son's age is x+5=15+5=20.

Father's age is 3x+5=45+5=50 which is 30 years more than son's age.

Answered by parasrathod0105
0

Answer:

Step-by-step explanation:

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