Math, asked by saman6344, 1 year ago

A man is 3 years older than his wife and four times as old as his son. if the son becomes 15 years old after 3 years, what is the present age of his wife

Answers

Answered by Tanzeel497
2
the present age of his wife is 45 years
Answered by ALTAF11
5
Let the age of man be x

wife's be y

and son's be z

•man is three times older than his wife.

x = 3 + y ....... ( i )

• Man is four times as old as his son

x = 4z ..... ( ii )

• Son age after 3 years is 15

z + 3 = 15

z = 15 - 3

z = 12

Putting the value of z in ( ii )

x = 4z

x = 4 × 12

x = 48


Putting the value of x in ( i )

x = 3 + y

48 = 3 + y

48 - 3 = y

45 = y


The age of his wife is 45 years.
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