Question

A man is 30 year older than his son. After 12 years the man will be twice as old as his son. Find their present ages

Answer 1

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Answer 2

let the son's age be x
father's age = x + 30
after 12 yrs
father's age = x + 42
son's age = x + 12
x + 42 = 2(x + 12)
x + 42 = 2x + 24
42 - 24 = 2x - x
18 = x
son's age is 18
father's age is 18 + 30 = 48