Math, asked by riteshsingh65, 10 months ago

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A man is 30 years older than his son. After four years he will be three times as
old as his son. Find their present ages

Answers

Answered by Anonymous
2

Answer:

child is 6 years old and his father is 36 years old

Step-by-step explanation:

let the age of son be x

then,the age of his father will be x+30

x+34=4(x+4)

x+34=4x+16

34-16=4x-x

18=3x

x=6

Answered by nitin009988
2

Answer:

let sons age be x

then the person's age be x+30

after four years , (x+4) 3 = x+30+4

3x+12 = x+34

2x = 22

x= 11

so, son's present age is 11 years

and father's present age is 11+30

= 41 years

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