A man is 30 years older than his son in 12 years the man will be 3 times as old as his son. Find their present age.
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Question:
A man is 30 years older than his son in 12 years the man will be 3 times as old as his son. Find their present age
Given:
Let present age of son = x
then man/father age will be (x + 30)
Man/father age = (30 + x + 12)
son age = x + 12
solution:
3(x + 12) = (48 + x)
3x - x = 48 - 36
2x = 6
x = 6/2
x = 3
son age is 3 years
man/father age is 30 + x = 33
30 + 3 = 33
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