A man is 32 years old and his son is 5 years old. How many years hence will be father's age be four times that of the son.
Answers
Answered by
45
Step-by-step explanation
Man's present age : 32 years
Son’s present age : 5 years
After ‘x’ years from now Father's age will be 4 times the age of the Son.
Therefore,
4(5+x) = 32+x
20+4x = 32+x
4x-x = 32–20
3x =12
x = 12/3
x = 4
That means after 4 years the father’s age will be 32+4 = 36 and son’s age will be 5+4 = 9 years.
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Answered by
29
Let the father age be (32+x)
The son age be (5+x)
A.T.Q,
32+x =4 (5+x)
32+x = 20+4x
32-20 = 4x-x
12 = 3x
x = 12÷3
x=4 years
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