Question

A man is 32 years older than his son 10 years ago he was 3 times as old as his son find the present age of each

Answer 1

Let the age of son is x years
Then his fathers age will be
$x + 32$
Before 10 years
Sons age
$x - 10$
Fathers age
$x + 32 - 10 = x + 22$
But Given condition
$x + 22 = 3(x - 10) \\ x + 22 = 3x - 30 \\ 3x - x - 30 - 22 = 0 \\ 2x - 52 = 0 \\ x - 26 = 0 \\ x = 26$
Age of son is 26 and father is 26+32=58

Answer 2

Step-by-step explanation:

Let the age of son be x years

Then his fathers age will be

x + 32x+32

Before 10 years

Sons age

x - 10x−10

Fathers age

x + 32 - 10 = x + 22x+32−10=x+22

But Given condition

\begin{lgathered}x + 22 = 3(x - 10) \\ x + 22 = 3x - 30 \\ 3x - x - 30 - 22 = 0 \\ 2x - 52 = 0 \\ x - 26 = 0 \\ x = 26\end{lgathered}

x+22=3(x−10)

x+22=3x−30

3x−x−30−22=0

2x−52=0

x−26=0

x=26

Age of son is 26 and father is 26+32=58