Question

A man is 32 years older than his son. Ten years ago he was three times as old as his son was then. Find the present age of each

Answer 1

Answer:

son-11 ,man-43

Step-by-step explanation:

let sons age be x

then, man's age is = x+32

Ten years ago

sons age will be = x-10

and man's age will be = x+32 -10

                                      = x+22

in th question it is given that man's age ten years ago=3x

so by this we can equate the two:

x+22 = 3x

=> x-3x = -22

=>-2x=-22

=>x= -22/-2

so x =11

sons age = 11

man's age = 32+11

                  = 43