A man is 37 year old and his sons are 8year and 3 year old respectively after how many years will he be twins as old as the sum of the ages of his sons?
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Man's age = 37
Sum of son's age = (8 + 3)
= 11
Let the number of years = x
So, After x years , sum of son's age will be twice of man's age.
37 + x = (11+x) * 2
37 + x = 22+2x
37 - 22 = 2x - x
15 = x
Answer = 15 years
Sum of son's age = (8 + 3)
= 11
Let the number of years = x
So, After x years , sum of son's age will be twice of man's age.
37 + x = (11+x) * 2
37 + x = 22+2x
37 - 22 = 2x - x
15 = x
Answer = 15 years
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