a man is 37 years old; his two sons are 8 years and 3 years old. after how many years will he be twice as old as their united age?
johnsonunni:
after 5 years man will be 42 and his two sons united age will be 21....
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present age of man= 37
present age of first boy =8
present age of second boy=3
add of two boys =11
let the age after many years=x
boys age=11+x
man age after many years =2x
=11x=37+2x
=2x-x=37-11
=x=26
the boys age is 26
man age =2*x
=2*26
=52
therefore if the sons age is 26 the man's age will be twice of them that is 52 years
present age of first boy =8
present age of second boy=3
add of two boys =11
let the age after many years=x
boys age=11+x
man age after many years =2x
=11x=37+2x
=2x-x=37-11
=x=26
the boys age is 26
man age =2*x
=2*26
=52
therefore if the sons age is 26 the man's age will be twice of them that is 52 years
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