Question

A man is 4 times as old as her daughter. After 16 e, he will be twice as old as her daughter find daughter's age.

Answer 1

let the daughter's age be x
man's age= 4x

after 16 years,
man's age = 4x+16
daughters age= x+16

therefore the equation is,
2(x+16)= 4x+16 (since the man will be twice the age of his daughter)
2x+32=4x+16
4x+16=2x+32
4x-2x= 32-16
2x= 16
x=16/2
x=8

therefore daughters present age will be 8 years

Answer 2

Answer:

Present age of Man = 32

Present age of Daughter = 8

Let the ;

Age of the Daughter be x

Age of Man = 4x

After 16 years ;

Age of Man = 4x + 16

Age of Daughter = x + 16

Age of Man after 16 years

= ( 4x + 16 ) = 2 ( x + 16 )

= 4x + 16 = 2x + 32

= 4x + 16 = 2x + 32

= 4x - 2x = 32 - 16

= 2x = 16

= x = 16 / 2

Hence;

Present Age of The Daughter ( x ) = 8

Present age of Man ( 4x ) = 4 ( 8 ) = 32