Question

a man is 4 times as old as her daughter. after 16 year he will be twice as old as her daughter find the daughter age

Answer 1

Hey !!


Let present age of daughter and man be x and 4X.



A/q



4X + 16 = 2 ( X + 16 )



4X + 16 = 2X + 32



4X - 2X = 32 - 16




2X = 16


X = 16/2

X = 8 years.


Present age of daughter = X = 8 years

Answer 2

Heya !!


Let present age of daughter be X year's.




Present age of Father = 4X year's.



After 16 years age of daughter = ( X + 16 ) year's.


After 16 years age of Father = ( 4X + 16 ) year's.



According to question,



Age of Father after 16 years = 2 ( Age of daughter after 16 years ).



4X + 16 = 2 ( X + 16 )



4X + 16 = 2X + 32



4X - 2X = 32 - 16



2X = 16



X = 8 year's.



Present age of daughter = 8 year's.