Question

a man is 4 times as old as her daughter.after 16 years,he will be twice as old as her daughter find daughter's age

Answer 1

Let the age of daughter be a

Father's age = 4a

After 16 years

Daughter's age = a +16

Father's age = 4a + 16

According to question

2(a+16) = 4a + 16

=> 2a +32 = 4a +16

=> 32 - 16 = 4a - 2a

=> 2a = 16

=> a = 8


Daughter's present age = 8 years

Father's present age = 32 years

Answer 2

man =4x daughter = ×
after 16 years
man =4x+16 = 2(x+16) daughter= x+16
4x+16= 2x+32
4x- 2x= 32-16
2x=16
x=6