A man is 4 times as old as his son, after 10 years father will be 10 years twice the son's age. find the age of father and son
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let the present age of son nd father be x yrs nd y yrs respectively......
ATQ.....
y = 4x ........(i)
After 10 yrs......
sons age = (x + 10) yrs
fathers age = (y + 10) yrs
y + 10 = 2 ( x + 10 )
=> 4x + 10 = 2x + 20 { from (i) }
=> 2x = 10
=> x = 5 yrs
y = 4x
= 4 × 5
= 20 yrs
Son's present age = 5 yrs
Son's present age = 5 yrsFather's present age = 20 yrs
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