Question

A man is 4 times as old as his son, after 10 years father will be 10 years twice the son's age. find the age of father and son​

Answer 1

let the present age of son nd father be x yrs nd y yrs respectively......

ATQ.....

y = 4x ........(i)

After 10 yrs......

sons age = (x + 10) yrs

fathers age = (y + 10) yrs

y + 10 = 2 ( x + 10 )

=> 4x + 10 = 2x + 20 { from (i) }

=> 2x = 10

=> x = 5 yrs

y = 4x

= 4 × 5

= 20 yrs

Son's present age = 5 yrs

Son's present age = 5 yrsFather's present age = 20 yrs

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