a man is 4 times as old as his son. After 10 years he will be as old has his son at that time find the present ages
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Your question is wrong as it should have father at the place of son in the second line. and answer according to the correct statement is - father = 56 ; son = 14
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Answer:
Man's age = 40 yrs.
Son's age = 10 yrs
Step-by-step explanation:
Let the Man's age be x years and his son's age be y years
- It is given :
x = 4y -------------- (i)
After 20 years their ages will be
Man : x + 20
Son : y + 20
x + 20 = 2 ( y + 20 ) ----------------- (ii)
Substituting value of x in equation (ii) with 4y
=> 4y + 20 = 2y + 40
=> 4y - 2y = 40 - 20
=> 2y = 20
=> y = 10 years
Using in eq (i)
x = 4y
=> x = 40 years
Man's age = 40 yrs.
Son's age = 10 yrs
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