Question

A man is 4 times as old as his son. After 12years he will be twice as old as his son. Find the age of his son​

Answer 1

Answer:

6years

Step-by-step explanation:

let the present age of son be 'x'

⇒ present man's age = 4x

AFTER 12 YEARS

age of son = x+12

age of man = 4x+12

given that, man age was twice the son age

⇒ 4x+12 = 2(x+12)

⇒ 4x+12 = 2x+24

⇒ 2x = 12

⇒ x = 6

∴ age of his son was x = 6years

Answer 2

suppose the age of the son is X

the his father's age is 4X

after 12 years son's age will be (X+12)

and his father's age will be (4X+12)

then,

2(X+12)=(4X+12)

X=6