A man is 4 times as old as his son . After 16 tears he will only twice old as his son ?
Answers
Answered by
1
Answer:
Let Age of son be - 'x'
and age of man be - '4x'
Now,
4x+16 = 2(x+16)
=> 4x+16= 2x+32
=> 4x-2x= 32-16
=> 2x = 16
So, x= 16/2 = 8
Now,
Age of son = x = 8
and Age of man is = 4x = 4×8 = 32
Answered by
0
Step-by-step explanation:
let son's age be x years
so man's age = 4x
now , after 16 years their ages will be -
man's age = 4x + 16
son's age = x + 16
Given that after 16 years man's age wil be 2 times his son's age , so , 4x + 16 = 2(x + 16)
4x + 16 = 2x + 32
2x = 16
x = 8
therefore son's age = 8
man's age = 4x = 4 × 8 = 32
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