Question

A man is 4 times as old as his son. After 16 years he will be only twice as old as his son. Find their present age

Answer 1

let the present age of the son be .x

and that of man be.y

then according to the question

case 1

y=4x ........eq.1

case 2,

y +16 = 2(x+16)

this implifies that

y +16= 2x +32

y-2x = 16

( putting value of y in here we get)

3x-2x = 16

x =16

HOPE IT HELPS PLS MARK AS BRIANALIST LMAO

Answer 2

Answer:

Let the present age of the son be x years.

the present age of his father = 4x years.

after 16 years,

Son’s age = (x + 16) and father’s age = (4x + 16) years

According to the question:

⇒ 4x + 16 = 2(x + 16)

⇒ 4x + 16 = 2x + 32

⇒ 4x – 2x = 32 – 16

⇒ 2x = 16

⇒ x = 16/2

⇒ x = 8

the present age of the son = 8 years,

And the present age of the father = 4x

                                                           = 4 x 8 = 32 years.