Question

A man is 4 times as old as his son after 16 years he will be only twice as old as his son find the the present age​

Answer 1

Let Son's age =x and Man's age =4x

After 16 years,

2(x+16)=4x+16

2x+32=4x+16

16=2x

x=8 years

∴ Son's age =8 years and Man's age =32 years.

I HOPE IT IS HELPFUL TO YOU!!

Answer 2

Answer:

x = 4y ---------- (1)

After 16 years,

age of father will be x+ 16

age of son will be y +16

Therefore, x + 16 = 2( y + 16)

x + 16 = 2y + 32

x = 2y + 16

or 4y = 2y + 16 {Using equation (a)}

2y = 16

y = 8

Plugging back the value of y in equation (1), we get:

x = 4*8 = 32

Hence, the present age of father is 32 years and present age of son is 8 years.