A man is 4 times as old as his son. After 16 years he will be only twice as old as his son. Find their present ages
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a man is 4 times as old as his son after 16 years he will be only twice as old as his son find their present age this is the answer for this question
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Answer:
Let the present age of the son be x years.
the present age of his father = 4x years.
after 16 years,
Son’s age = (x + 16) and father’s age = (4x + 16) years
According to the question:
⇒ 4x + 16 = 2(x + 16)
⇒ 4x + 16 = 2x + 32
⇒ 4x – 2x = 32 – 16
⇒ 2x = 16
⇒ x = 16/2
⇒ x = 8
the present age of the son = 8 years,
And the present age of the father = 4x
= 4 x 8 = 32 years.
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