Math, asked by indiramurugesan, 5 months ago

A man is 4 times as old as his son. After 16 years, he will be only
twice as old as his son. Find their present ages.​

Answers

Answered by Anonymous
3

Answer:

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Step-by-step explanation:

Let Son's age =x and Man's age =4x

After 16 years,

2(x+16)=4x+16

2x+32=4x+16

16=2x

x=8 years

∴ Son's age =8 years and Man's age =32 years.

Answered by amrpurikrishiv10
1

Answer:

Answer:

At present :

At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

Step-by-step explanation:

At present:

Age of son = x years

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given,

Therefore,

At present :

Son age = x = 8 years

Father age = 4x=4×8 = 32 years

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