Question

A man is 4 times as old as his son. after 16 years he will be only twice as old as his son. find their present ages ​

Answer 1

Answer:

Father's Present Age = 32 years

His son's Present age = 8 years

Step-by-step explanation:

Let the son's present age be x

Then, father's present age would be 4x

Fathers age after 16 years = 16+4x

Son's age after 16 years = 16+x

According to the question, after 16 years, the father's age would be only 2 times his son.

2(x+16) = 4x +16

2x + 32 = 4x+16

4x+16 = 2x+32

4x-2x = 32-16

2x = 16

x = 16/2

x = 8

Present age of father = 4x = 4×8 = 32 years

Present age of son = x = 8 years

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Answer 2

Answer:

Let the present age of the son be x years.

the present age of his father = 4x years.

after 16 years, Son’s age = (x + 16) and father’s age = (4x + 16) years According to the question:

⇒ 4x + 16 = 2(x + 16)

⇒ 4x + 16 = 2x + 32

⇒ 4x – 2x = 32 – 16

⇒ 2x = 16

⇒ x = 16/2

⇒ x = 8 the present age of the son = 8 years,

And the present age of the father = 4x = 4 x 8 = 32 years.