Question

A man is 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find the their present ages.​

Answer 1

Answer:

Son's age =8 years and Man's age =32 years.

Step-by-step explanation:

Let Son's age =x and Man's age =4x

After 16 years,

2(x+16)=4x+16

2x+32=4x+16

16=2x

x=8 years

∴ Son's age =8 years and Man's age =32 years.

Answer 2

Answer:

son = 8 years, man = 32 years

Step-by-step explanation:

Given that a man is 4 times as old as his son. After 16 years, he will be only twice as old as his son.

We need to find out the present age of son and man.

Let's say the present of son is x years.

Man is 4 times as old his son. Therefore, age of man is 4x.

Now,

After 16 years:

• Age of son = (x + 16) years
• Age of man = (4x + 16) years

As per question, "After 16 years, he will be only twice as old as his son."

→ 4x + 16 = 2(x + 16)

→ 4x + 16 = 2x + 32

→ 4x - 2x = 32 - 16

→ 2x = 16

→ x = 8

Age of son = x = 8 years

Age of man = 4x = 4(8) = 32 years

Therefore, the present age of son is 8 years and man is 32 years.