Question

a man is 4 times as old as his son. after 16 years he will be only twice as old as his son. find their present ages.

Answer 1

At present:
Let the age of son is x
fathers age=4x
After 16 years:
son's age= x+16
father's age=4x+16
condition: 4x+16=2(x+16)
4x+16=2x+32
4x-2x=32-16
2x=16
x=8 years
Therefore, son's age is x= 8 yrs
father's age is 4x= 4(8)=32 yrs.

Answer 2

Answer:

Man's age = 32

Step-by-step explanation:

Son = x

Man = 4x

After 16 years

Son = x + 16

Man = 2x + 16

4x =  2x + 16

4x - 2x = 16

2x = 16

x = $\frac{16}{2}$

x = 8

Therefore, Son's age = 8

Man's age = 4x

                 = 4 × 8

                 = 32