Math, asked by singhrakesh8759, 29 days ago

A man is 4 times as old as his son. After 18 years he will be only twice as old as his son
Find their present ages.​

Answers

Answered by sneha140408
1

Answer:

Son's age =9 years , Man's age=36 years

Step-by-step explanation:

Let son's age be =x , then, Man's age= 4x

After 18 years =

2( x+18) = 4x+18

= 2x+36=4x+18

= 2x-4x= 18-36

= -2x= -18 ( -ve signs will cancel out)

= x= 18/2

= x= 9

Son's age = x= 9

Man's Age = 4x= 4*9= 36

Hope it's clear to you.

Answered by Trishala1011
0

Answer:

abc

Step-by-step explanation:

I Clarkston ALM Ajay jaati U suvichar suvichar clickhi

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