a man is 4 times as old as his son after 20 years he will be twice as old as his son at that Time find his present age
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Let the son's age be x
His father's age will be 4x
Equaton formed will be.... x = 4x.............(1)
After 20 years:
Son's age will be 20+x
Father's age will be 2(20+x)
Equation will be ...... 20+x = 2(20+x)..........(2)
Step-by-step explanation:
Take 1 and 2
Solve by any method....
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