Question

A man is 4 times as old as his son. After 20 years he will be twice

as old as his son. Find their present ages.​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let the present age of son be x

Then father's present age will be 4x

After 20 years

age is son=x+20

age of father=4x+20

A.T.Q

4x+20=2 (x+20)

4x+20=2x+40

2x=20

x=10

Present age of son is 10

and present age of father is 40