A man is 4 times his son’s age . After 5 years, he will be 3 times as old as his son .Find their present ages.
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Answer:
let the age of son be y a d man box
atq
x=4y
x-4y=0(1*)
x+5=3(y+5)
x+5=3y+15
x-3y=10(2*)
sub eqa 1 n2
-y=-10
y=10
putting y =10,in equ 1
x-4(10)=0
×=40
so, age of father =40years
and age of son =10years
plz mark me brainliest
Anonymous:
ok...
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