A man is 40 m behind the bus. when the bus starts accelerating from rest with constant acceleration 1.25 m/s2. with what minimum constant velocity should the man start runing to catch the bus?
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as we know
v square = u square + 2× a × distance
v square = 0 +2×1.25×40
v square = 100
v square = √100
v square = 10m/s
v square = u square + 2× a × distance
v square = 0 +2×1.25×40
v square = 100
v square = √100
v square = 10m/s
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