a man is 40 year old and his son is 14 year old how many year will the father he twice as old as his son
Answers
Answered by
42
man's age = 40(x)
son's age = 14(y)
(x+a) = 2 (y+a)
40+a = 2(14+a)
40+a = 28+2a
40-28 = a
12 = a
after 12 years, his son will be of 26 and man will be of 52, that is,twice
son's age = 14(y)
(x+a) = 2 (y+a)
40+a = 2(14+a)
40+a = 28+2a
40-28 = a
12 = a
after 12 years, his son will be of 26 and man will be of 52, that is,twice
Answered by
20
Answer:
12 years
Step-by-step explanation:
Let the years=x
According to the question=
40+x=2(14+x)
40+x=28+2x
40-28=2x-x
x=12
Verification:
After 12 years
man's age : 40 years +12 years
=52 years
son's age : 14 years+12 years
= 26 years
Hence verified 52 years is twice of 26 years
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