Question

A man is 40 years old and his son is 14 years old how many years will the father be twice an old an his son​

Answer 1

Step-by-step explanation:

Man's age = 40

Sons's age = 14

Let

Number of years = x

father will be = 40 + x

Son will be = 14 + x

Twice the age of son after x years = father's age after x years

2(14+x)=40+x

28+2x=40+x

2x-x=40-28

x=12

After 12 years father will be twice as old as his son.

Check

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Man's age = 40 +12 = 52 (which is twice of 26)

Sons's age = 14 + 12 = 26