Question

A man is 40 years old and his son is 14 years old. in how many years will the father be twice as old as his son

Answer 1

Answer:

Step-by-step explanation:

man's age = 40(x)

son's age = 14(y)

(x+a) = 2 (y+a)

40+a = 2(14+a)

40+a = 28+2a

40-28 = a

12 = a

after 12 years, his son will be of 26 and man will be of 52, that is,twice

Answer 2

Answer:

12 years

Hope it will help you.. Thank You..

Step-by-step explanation:

Let, after 'x' years the father will be twice as old as his son

Equation,

40+x = 2 ( 14 + x )

or, 40 + x = 28 +2x

or, x - 2x = 28 - 40

or, - x = - 12

or, x = 12