A man is 40 years old and his son is 14 years old. In how many years will thefather be twice as old as his son?
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Answer: man's age = 40(x)
son's age = 14(y)
(x+a) = 2 (y+a)
40+a = 2(14+a)
40+a = 28+2a
40-28 = a
12 = a
after 12 years, his son will be of 26 and man will be of 52, that is,twice
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