A man is 40 years older than his son. If the sum of their ages is 82 years, find the age of his son and his father.
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let the age of son be x
then by the question age of father is x+40
now the sum of ages of father and son is 82
so .... x +x+40=82
.......2x =82 -40 ( + becomes minus when it crosses = sign)
.........2x= 42
.........x=42 ÷2 (× becomes ÷ when it crosses = sign)
......x=21years
father =x +40
so 21+40
=61 years
father's age is 61 years and sons age is 21 years
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then by the question age of father is x+40
now the sum of ages of father and son is 82
so .... x +x+40=82
.......2x =82 -40 ( + becomes minus when it crosses = sign)
.........2x= 42
.........x=42 ÷2 (× becomes ÷ when it crosses = sign)
......x=21years
father =x +40
so 21+40
=61 years
father's age is 61 years and sons age is 21 years
IF U LIKE MY ANSWER THEN DO MARK ME AS BRAINLIEST U CAN ALSO FOLLOW HAPPY ANSWERING
helpme94:
thanks for fast answer!
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Solutions :-
let the age of son be x
father age will be x+40
sum of ages of father and son is 82
A/q
x +x+40=82
2x =82 - 40
2x= 42
x = 21years
father age = x +40 = 21+40 =61 years
father's age is 61 years and sons age is 21 years
Thanks
let the age of son be x
father age will be x+40
sum of ages of father and son is 82
A/q
x +x+40=82
2x =82 - 40
2x= 42
x = 21years
father age = x +40 = 21+40 =61 years
father's age is 61 years and sons age is 21 years
Thanks
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