Question

A man is 40 yrs old and his son is 14 yrs old in how many yrs the father will be twice as old as his son

Answer 1

Answer:

The answer is:-

After 12 years later the father will be twice as old as his son.

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Answer 2

Answer:

12 years

Step-by-step explanation:

Let the no. of years be x.

Age of father after x years = 40 + x

Age of son after x years = 14 + x

According to question,

40+x = 2 ( 14+x)

40+x. = 28+2x

40-28 = 2x-x

x = 12

Ans---> After 12 years, the father will be twice as old as his son.