Question

A man is 41 years old and in seven years he will be four times as old as his son at that time. How old is his son now?

Answer 1

Answer:

3

Step-by-step explanation:

Present age of the man = 4

After 7 years

Man’s age = 41+7=48

Let age of son at that time be x

Then,

4x = 48

x = 48/4

x = 12

To find the present age we will do -7

Present age = x-7

Present age = 12-7

Present age = 3

Hop this helps you

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