A man is 42 years old and his son is 12 years old.How many years hence will the father's age six times that of his son?
Answers
Answered by
14
Age of father = 42
Age of son = 12
Let the years needed be 'x'
ATQ
(42+x) = 6(12+x)
42 + x = 72 + 6x
42 - 72 = 6x - x
-30 = 5x
x = -30/5 = -6
So his father's age was six times of his son's age 6 years ago.
Age of son = 12
Let the years needed be 'x'
ATQ
(42+x) = 6(12+x)
42 + x = 72 + 6x
42 - 72 = 6x - x
-30 = 5x
x = -30/5 = -6
So his father's age was six times of his son's age 6 years ago.
annu86:
thnks
wlcm
Answered by
11
42-x=6(12-x)
42-x=72-6x
-x+6x=72-42
5x=30
X=6
If the fathers age was 36 and the sons age was 6years that's is 6years ago
42-x=72-6x
-x+6x=72-42
5x=30
X=6
If the fathers age was 36 and the sons age was 6years that's is 6years ago
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