A man is 42 years old and his son is 12 years old. In how many years will the age of the son be half of his father at that time. PLS EXPLAIN
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Answered by
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Let the no: of years be x
12+x= (42+x)/2
24+2x=42+x
x=42-24
=18
Therefore, After 18 years the age of the son will be half of his father at that time.
12+x= (42+x)/2
24+2x=42+x
x=42-24
=18
Therefore, After 18 years the age of the son will be half of his father at that time.
MRUGANKKUL:
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Answered by
2
Let the age of the son be half of his father after x years.
Age of the man = 42 + x.
Age of the son = 12 + x.
Therefore,
Age of the son after x years = Half of the age of his father after x years.
12 + x = 1/2(42 + x)
2(12 + x) = (42 + x)
24 + 2x = 42 + x
24 = 42 + x - 2x
24 = 42 - x
24 - 42 = -x
-18 = -x
x = 18.
Therefore In 18 years the age of the son will be half the age of his father.
Hope this helps!
Age of the man = 42 + x.
Age of the son = 12 + x.
Therefore,
Age of the son after x years = Half of the age of his father after x years.
12 + x = 1/2(42 + x)
2(12 + x) = (42 + x)
24 + 2x = 42 + x
24 = 42 + x - 2x
24 = 42 - x
24 - 42 = -x
-18 = -x
x = 18.
Therefore In 18 years the age of the son will be half the age of his father.
Hope this helps!
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