Math, asked by bajajjashan5, 5 months ago

a man is 42 years old and his son is 12 yrs old . how many years ago was the father's age 6 Times of the son?


soon the answer is 6 but we also have to put - sign that,s not clear
# jannat # kamlo​

Answers

Answered by alihelal683
1

Answer:

6 years

Step-by-step explanation:Let the years be x years before which his father is 6 times his son,

42-x=6(12-x)

=>x=6 years.

Answered by srishti539
1

Let before x years, father's age was six times son's age.

Before x years their age was,

Father’s age = 42-x

Son's age = 12-x

Now, according to question,

42-x = 6*(12-x)

42-x = 72–6x

-x +6x = 72–42

5x= 30

x=6

Hence before 6 years father's age was six times son's age

We can verify also

42–6 = 36. Father's age

12–6 = 6. son's age

6*6=36

Hence the answer is 6.

Hope that will help you alot

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