Question

A man is 45 m behind the bus when the bus start accelerating from rest with acceleration 2.5 m/s2. with what minimum velocity should the man start running to catch the bus?

Answer 1

as we know
v square = u square + 2 a × distance
v square = 0+ 2×2.5×45
v square = 225
v = √225
v = 15 m/s

Answer 2

Give man a chance to will get the transport after 't' sec . So he will cover separate ut.

So also remove gone by the transport will be 12at2.

As we probably am aware v square = u square + 2 a × separate v square = 0 + 2 × 2.5 × 45 v square = 225 v = √225 v = 15 m/s.