Question

a man is 48m behind a bus which is at rest the bus starts accelatred at the rate of 1m/s2,at the same time the man starts running with uniform velocity of 10/s what is the minimum time in which the man catches the bus?

Answer 1

here the idea is that when the man catches the bus, the final position of bus and man is sama and this would happen in same time.
x-48= 0+ 1/2 1 t*2 non uniform motion
And x = 10 t. uniform motion of boy.
Now solve for t and u will get the answer