Question

a man is 4times as old as his son after 16 years he will be only twicE as old as his son. find the their present age​

Answer 1

Step-by-step explanation:

Let the present age of father be x and the son be y. 

Now, x = 4y ---------- (1) 

After 16 years,

age of father will be x+ 16

age of son will be y +16 

Therefore, x + 16 = 2( y + 16)

x + 16 = 2y + 32

x = 2y + 16

or 4y = 2y + 16 {Using equation (a)}

2y = 16

y = 8 

Plugging back the value of y in equation (1), we get:

x = 4*8 = 32 

Hence, the present age of father is 32 years and present age of son is 8 years.